f.3 math..指數定律

2007-09-25 8:22 pm
(2^x)- -(2^x-1)=4

(3^x+2) - (3^x) = 72

2(3^x+1) - 5(3^x) = 9

回答 (1)

2007-09-25 8:30 pm
✔ 最佳答案
1)
2^x - 2^(x-1) = 4
2^x (1 - 2^-1) = 4
2^x (1/2) = 4
2^x = 8
2^x = 2^3
x = 3

2)
3^(x+2) - 3^x = 72
3^x (3^2 - 1) = 72
3^x (9-1) = 72
3^x (8) = 72
3^x = 9
3^x = 3^2
x = 2

3)
2*3^(x+1) - 5(3^x) = 9
3^x(2*3 - 5) = 9
3^x (6-5) = 9
3^x = 9
3^x = 3^2
x = 2
參考: I am a maths tutor


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