Suppose 2 is a root of the quadratic equation x^2-5x+k(1-x)=0
a Find the value of k
b Finf the other root of the equation .
F4 Math一問~~~~~
2007-09-25 2:05 am
回答 (2)
2007-09-25 2:09 am
✔ 最佳答案
A)As the question mentioned, 2 is a root of the equation
Therefore
Put x=2 into the equation
(2)^2 - 5(2) + k(1-2) = 0
4 - 10 + k(-1) = 0
-6 - k = 0
k = -6
B)
Put k=-6 into the equation
x^2 - 5x + (-6)(1-x) = 0
x^2 - 5x - 6 + 6x = 0
x^2 + x - 6 = 0
(x+3)(x-2) = 0
Therefore another root is -3
參考: Me
2007-09-25 2:23 am
a. Substitute x=2 into x^2 -5x + k(1-x) =0
2^2 - 5(2) + k(1-2)=0
4-10-k=0
k= - 6
b. x^2-5x-6(1-x)=0
x^2+x-6=0
(x+3)(x-2)=0
So the another root is -3.
2^2 - 5(2) + k(1-2)=0
4-10-k=0
k= - 6
b. x^2-5x-6(1-x)=0
x^2+x-6=0
(x+3)(x-2)=0
So the another root is -3.
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