a-maths!!!!!!

2007-09-24 4:08 am
若一動圓C通過點(-1,2),且與直線x-2y+3=0相切,試求C的圓心之軌距方程。

回答 (1)

2007-09-24 4:30 am
✔ 最佳答案
Let G(x,y) be the centre
distant between G and C = distant between G and the equation "x-2y+3=0"
√(x+1)² + (y-2)² = (x-2y+3) / √(1²+2²)
√5 √(x² + y² + 2x - 4y + 5) = x - 2y + 3
5x² + 5y² + 10x - 20y + 25 = (x - 2y + 3)²
5x² + 5y² + 10x - 20y + 25 = x² - 4y²- 4xy + 6x - 12y + 9
4x² + 9y² + 4x - 8y + 4xy + 16 = 0


收錄日期: 2021-04-23 20:34:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070923000051KK04725

檢視 Wayback Machine 備份