plz help me to answer the question.if you do not know the answer,plz answer no.i need the steep~thank for your help~
1a)Factorize ab-bc.
(b) Expand 2x(x+3)-5(x+3).
(c)Using the result of (a) and (b),and let a+2x,b+x+3 and c+5,factorize 2x^2+x-15.
f.2 mathz ple help me~
2007-09-23 6:08 pm
回答 (3)
2007-09-23 6:49 pm
✔ 最佳答案
I can help you:1.Factorize ab-bc
ab-bc
=b(a-c)
2.Expand 2x(x+3)-5(x+3) *in the answer,you should put (x+3) at the front.
2x(x+3)-5(x+3)
= (x+3)(2x-5)
3.Using the result of (a) and (b)
ab-bc
=b(a-c)
2x(x+3)-5(x+3)
= (x+3)(2x-5)
2x^2+x-15
=2x^2+6x-5x-15
=2x(x+3)-5(x+3)
=(x+3)(2x-5)
參考: I am a Form 2. student in an English school
2007-09-23 6:15 pm
1a)Factorize ab-bc.
=b(a-c)
(b) Expand 2x(x+3)-5(x+3).
=2x^2+6x-5x-15
=2x^2+x-15
(c)Using the result of (a) and (b),and let a+2x,b+x+3 and c+5,factorize 2x^2+x-15.
by the result of (b)
2x^2+x-15
=2x(x+3)-5(x+3)
Let a=2x, b=(x+3), c=5
By the result of (a)
=2x(x+3)-5(x+3)
=(x+3)(2x-5)
=b(a-c)
(b) Expand 2x(x+3)-5(x+3).
=2x^2+6x-5x-15
=2x^2+x-15
(c)Using the result of (a) and (b),and let a+2x,b+x+3 and c+5,factorize 2x^2+x-15.
by the result of (b)
2x^2+x-15
=2x(x+3)-5(x+3)
Let a=2x, b=(x+3), c=5
By the result of (a)
=2x(x+3)-5(x+3)
=(x+3)(2x-5)
2007-09-23 6:12 pm
ab-bc
=b(a-c)//
2x(x+3)-5(x+3)
=(x+3)(2x-5)//
2x^2+x-15
=2x^2+6x-5x-15
=2x(x+3)-5(x+3)
=(x+3)(2x-5)//
=b(a-c)//
2x(x+3)-5(x+3)
=(x+3)(2x-5)//
2x^2+x-15
=2x^2+6x-5x-15
=2x(x+3)-5(x+3)
=(x+3)(2x-5)//
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