Help!!!!!Quick,please!!!!

3x+2y=2 ...(1)
{
x+y+2=0 ...(2)

從(2),
x+y+2=0
x = -2-y ...(3)

把(3)(1)
3(-2-y)+2y=2
-6-3y+2y =2
y =-8

把y=-8代入(2)
x+(-8)+2=0
x-8+2 =0
x =6

3x + 2y = 2 .... (1)
x + y + 2 = 0 .... (2)

From eq (1). x = -y-2 .... (3)

Substitue (3) into (1)

3(-y-2) + 2y = 2
-3y-6+2y=2
-y=8
y=-8

When y = -8,

x + y + 2 = 0
x -8+2= 0
x= 6

Other easy method,

eq (2) * 3
3x + 3y + 6 = 0 ........ (3)

eq(1) - eq (3)
3x+2y-3x-3y-6 = 2
-y = 8
y = -8

Substitue y = -8 to eq (2)

x - 8 + 2 = 0
x = 6