更新1:
I have the answer, but i don't know how to do it!!!!!
更新2:
The answer is: - m ( 3x - y )( x - 3y )
因式分解: m(x+y)^2 - 4m(x-y)^2
回答 (4)
2007-09-23 7:58 am
✔ 最佳答案
m(x+y)^2 - 4m(x-y)^2= m [ ( x + y )^2 - 4 ( x - y )^2 ] [ Take out m as common factor ]
= m [ ( x + y ) + 2 ( x - y ) ] [ ( x + y ) - 2 ( x - y ) ] [By a^2-b^2 = ( a + b )( a - b ) ]
= m ( x + y + 2x - 2y )( x + y - 2x + 2y )
= m ( 3x - y )( - x + 3y )
= - m ( 3x - y )( x - 3y )
參考: My Maths Knowledge
2007-09-23 8:11 am
m(x+y)^2-4m(x-y)^2
=m[(x+y)^2-4(x-y)^2]
=m{(x+y)^2-[2(x-y)]^2}
=m{[x+y+2(x-y)] [x+y-2(x-y)]}
=m(3x-y)(y-x)
i hope it is correct....
=m[(x+y)^2-4(x-y)^2]
=m{(x+y)^2-[2(x-y)]^2}
=m{[x+y+2(x-y)] [x+y-2(x-y)]}
=m(3x-y)(y-x)
i hope it is correct....
參考: By myself
2007-09-23 8:01 am
exp = m(x^2+2xy+y^2)-4m(x^2-2xy+y^2)
= mx^2+2mxy+my^2-4mx^2+8mxy-4my^2
=-3mx^2+10mxy-3my^2
=-(3mx^2+10mxy+3my^2)
=-m(3x^2+10xy+3y^2)
=-m(3x+1)(x+3)
ANS = -m(3x+1)(x+3)
= mx^2+2mxy+my^2-4mx^2+8mxy-4my^2
=-3mx^2+10mxy-3my^2
=-(3mx^2+10mxy+3my^2)
=-m(3x^2+10xy+3y^2)
=-m(3x+1)(x+3)
ANS = -m(3x+1)(x+3)
參考: myself
收錄日期: 2021-04-19 22:29:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070922000051KK05756