點解副副會得正？
回答 (5)
2007-09-22 6:36 pm
✔ 最佳答案
舉個實例,1 - (-1) =2
假設你有一個手袋 = 1
唔見左一個手袋 = -1
有一個手袋 減去 唔見左既一個手袋 = 你要有 2 個手袋
數理問題.
2007-09-22 9:32 pm
We can use patten to understand this:
1x2=2
1x1=1
1x0=0
Because the result decreases gradually, so we can predict that:
1x(-1)=(-1)
If
1x(-1)=(-1),
then
(-1)x2=(-2)
(-1)x1=(-1)
(-1)x0=0
Using the equations above, we can predict that
(-1)x(-1)=1
So, when two neg. no. are multiplied together, the result will be a pos. no.
1x2=2
1x1=1
1x0=0
Because the result decreases gradually, so we can predict that:
1x(-1)=(-1)
If
1x(-1)=(-1),
then
(-1)x2=(-2)
(-1)x1=(-1)
(-1)x0=0
Using the equations above, we can predict that
(-1)x(-1)=1
So, when two neg. no. are multiplied together, the result will be a pos. no.
2007-09-22 6:50 pm
負負得正是應用在乖除數之上,不是加減數
1+(-1)=(0),因為可以寫成(+1)+(-1)=(0)
(-1)+(-1)=(-2)
(-1)+(+1)=(0)
(+1)+(+1)=(+2)
之於
(+1)x(+1)=(+1)
(-1)x(-1)=(+1),兩個負值相消,負負得正
(+1)x(+1)=(+1)正正得正
(+1)x(-1)=(-1)正負得負
(-1)x(+1)=(-1)負正得負
2007-09-22 10:53:42 補充：
還有是 (+1)-(-1)=(+2)套用回(+1)-(+1)=(0)
1+(-1)=(0),因為可以寫成(+1)+(-1)=(0)
(-1)+(-1)=(-2)
(-1)+(+1)=(0)
(+1)+(+1)=(+2)
之於
(+1)x(+1)=(+1)
(-1)x(-1)=(+1),兩個負值相消,負負得正
(+1)x(+1)=(+1)正正得正
(+1)x(-1)=(-1)正負得負
(-1)x(+1)=(-1)負正得負
2007-09-22 10:53:42 補充：
還有是 (+1)-(-1)=(+2)套用回(+1)-(+1)=(0)
2007-09-22 6:44 pm
e.g. 1- (- 1)
我"唔要"(-) "負數"(-1) 咪即係等如正數囉~
會唔會容易明D?
我"唔要"(-) "負數"(-1) 咪即係等如正數囉~
會唔會容易明D?
2007-09-22 6:39 pm
因為一個負數 + 一個負數 = 一個正數
負負得正
正正得正
負正得負
正負得負
負負得正
正正得正
負正得負
正負得負
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https://hk.answers.yahoo.com/question/index?qid=20070922000051KK01026