[(2^2n+1)+7(2^n)]/4(2^n)
唔識計，要步驟
thz~
~指數定律~
2007-09-22 2:23 am
回答 (1)
2007-09-22 2:26 am
✔ 最佳答案
[22n+1 + 7(2n)]/4(2n) = [2 X 2n + 7 X 2n]/4(2n)
= (2 + 7)(2n)/4(2n)
= 9/4
2007-09-24 17:22:26 補充：
Sorry, 更正如下:[2^2n 1 7(2^n)]/4(2^n)= [2 X 2^2n 7(2^n)]/4(2^n)= 2/4 [2^(2n-n)] 7/4= 1/2 (2^n) 7/4
參考: Myself~~~
收錄日期: 2021-04-13 13:34:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070921000051KK02459