Law of Indices.. thx!!

Shing Hin

2007-09-22 2:11 am

1. [(-27x^-2 y^4 z^-1) / ( 3^6 x^-6 xy^-2 z^0)]^-2
2. [(2a^-3 b) / (2^-2 a^-4)]^-1 * [(18a^-4 / 3^3 b^-3 a^3)]^2
3. [(4m^2 n^-2) (-8m^-3 n^-2)^-2 ] / (16^-1 m^-3 n^-10)
4. [(3p^-2 q^3)^2 (6p^2 q^3) ^-2] / (-2p^-3 q^0 )

THX!!!

回答 (1)

Audrey Hepburn

2007-09-22 2:23 am

✔ 最佳答案

1. [(-27x-2y4z-1)/(36x-6xy-2z0)]-2
= (-27/36 x-2-(-6)-1y4-(-2)z-1)-2
= (-1/27 x3y6z-1)-2
= 272(1/-1)2x3(-2)y6(-2)z-1(-2)
= 729x-6y12z2
= 729y12z2/x6

2. [(2a-3b)/(2-2a-4)]-1 X [18a-4/33b-3a3]2
= [21-(-2)a-3-(-2)b1]-1 X [18/27 a-4-3b-(-3)]2
= (8a-1b)-1 X (2/3 a-7b3)2
= 1/8 a-1(-1)b-1 X 2/3 a-7(2)b3(2)
= 1/12 a1+(-14)b-1+6
= 1/12 a-13b5
= b5/12a13

3. [(4m2n-2)(-8m-3n-2)-2]/(16-1m-3n-10)
= 4 X (-8)-2 X 16 m2+(-3)(-2)-(-3)n-2+(-2)(-2)-(-10)
= m11n12

4. [(3p-2q3)2(6p2q3)-2]/(-2p-3q0)
= 3 X 6 / (-2) p-2(2)+2(-2)-(-3)q3(2)+3(-2)
= -9p-5
= -9/p5

參考: Myself~~~

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