1.if log(x-y)=2+log y,,express x in the trems of y
2.consider 2 log y-log√x=2,,express x in the trems of y
Maths Log
2007-09-20 7:37 am
回答 (2)
2007-09-20 8:01 am
log(x-y)=2+logy
log(x-y)=log100+logy
log(x-y)=log100y
x-y=100y
x=101y
2logy-log√x=2
logy^2-logx^1/2=log100
y^2
log(----------)=log100
x^1/2
y^2
----------=100
x^1/2
y^2=100 x^1/2
y^4=10000 x
x=y^4/10000
log(x-y)=log100+logy
log(x-y)=log100y
x-y=100y
x=101y
2logy-log√x=2
logy^2-logx^1/2=log100
y^2
log(----------)=log100
x^1/2
y^2
----------=100
x^1/2
y^2=100 x^1/2
y^4=10000 x
x=y^4/10000
2007-09-20 7:59 am
log(x-y)=2+logy
x-y=100+y
x-100=2y
x=2y+100
2 log y-log√x=2
2logy- 1/2 logx=2
1/2 logx=2logy -2
logx=2(2logy -2)
x=4y-100
x-y=100+y
x-100=2y
x=2y+100
2 log y-log√x=2
2logy- 1/2 logx=2
1/2 logx=2logy -2
logx=2(2logy -2)
x=4y-100
參考: myself
收錄日期: 2021-04-13 13:33:44
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