因式分解~~~~~~~

👨🏻‍🏫 學術台數學

2007-09-20 6:53 am

今日狀態唔太好~

雖然我係咁計一定計到

但我唔想計

3(6^2-5x-6)=0

回答 (2)

2007-09-20 7:01 am

✔ 最佳答案

3(6x^2-5x-6)=0
6x^2-5x-6=0
(2x - 3)(3x+2) = 0
x = 3/2 or -2/3

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2007-09-21 2:49 am

3(6^2-5x-6)=0
3(36-5x-6)=0
3(30-5x)=0
30-5x=0
x=6

參考: myself

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