中二數學(~急~)

2007-09-20 2:38 am
恆等式
1.(-7p+9p)²

回答 (5)

2007-09-20 2:57 am
✔ 最佳答案
(a+b)^2
=a^2+2ab+b^2

所以

(-7p+9p)²
=(-7p)^2+2(-7p)(9p)+(9p)^2
= 49p^2-126p^2+81p^2
=4p^2

beside,
(a+b)(a-b)
=a^2-b^2
參考: 自己
2007-09-24 4:45 am
(-7p+9p)²
=49p²+81p²
=130p²
希望幫到你
有咩唔識再搵我msn:[email protected]
參考: me
2007-09-20 3:02 am
=(-7p)^2+2(-7p)(9p)+(9p)^2
=49p^2-126p^2+81p^2
=4p^2

或者=(9p-7p)^2
=(9p)^2-2(7p)(9p)+(7p)^2
=81p^2-126p^2+49p^2
=4p^2

(^2)=2次方
希望幫到你^^
參考: 自己
2007-09-20 2:42 am
.(-7p+9p)²
=49p^2+81p^2
=p^2(49+81)
=p^2(130)
=130p^2
參考: own
2007-09-20 2:41 am
130p²

2007-09-19 18:42:46 補充:
(-7)²p² (9)²p²=130p²我想是差唔多= =
參考: me


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