[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
個答案係-6,我想知中間點計出黎,姐係要個步驟
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
個答案係+19又3分之1,我想知中間點計出黎,姐係要個步驟
中一數學功課問題,聽日交(10分!!!!!!!!!!!!!!!!)
2007-09-19 5:59 am
回答 (5)
2007-09-19 6:14 am
✔ 最佳答案
聽日就交即刻做比你睇
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[-26-(-8)]÷3
=-6
你最好將d小數轉做分數睇
0.5=1/2
-0.5=-1/2
0.75=3/4
[+(1-2/3)-(-12)×(+3/8)]÷1/4
=[(3/3-2/3)-(-4.5)]×4
=[1/3+9/2]×4
=29/6 ×4
=58/3
=19又3分1
中學生...要用多d假分數
2007-09-19 6:53 am
1.[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
＝(-13÷0.5+16×0.5)÷(－0.75×4)
＝（-26+8）÷(-3)
＝(-18)÷(-3)
＝6
2.[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
＝（1-2/3＋12×3/8）÷1/4
＝（1-2/3＋9/2）×4
＝（1/3＋9/2）×4
＝19又3分之1
＝(-13÷0.5+16×0.5)÷(－0.75×4)
＝（-26+8）÷(-3)
＝(-18)÷(-3)
＝6
2.[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
＝（1-2/3＋12×3/8）÷1/4
＝（1-2/3＋9/2）×4
＝（1/3＋9/2）×4
＝19又3分之1
2007-09-19 6:30 am
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[(-26)-(-8)]÷(-3)
=(-18)÷(-3)
=+6
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[(+3分之1)-(4又2分之1]÷4分之1
=[(+3分之1)+4又2分之1]÷4分之1
=(+4又6分之5)÷4分之1
=+19又3分之1
=[(-26)-(-8)]÷(-3)
=(-18)÷(-3)
=+6
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[(+3分之1)-(4又2分之1]÷4分之1
=[(+3分之1)+4又2分之1]÷4分之1
=(+4又6分之5)÷4分之1
=+19又3分之1
參考: Me
2007-09-19 6:23 am
第一題
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[(-10)-8]÷3
=(-18)÷3
=-6
第二題
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[3分之1)+2分之9)]÷4分之1
=[6分之2+6分之27]÷4分之1
=6分之29×4
=3分之58
=19又3分之1
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[(-10)-8]÷3
=(-18)÷3
=-6
第二題
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[3分之1)+2分之9)]÷4分之1
=[6分之2+6分之27]÷4分之1
=6分之29×4
=3分之58
=19又3分之1
參考: 自己計
2007-09-19 6:18 am
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[ (-26) - (-8) ]÷(-3)
=(-18) ÷ (-3)
= -6
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[1/3 - (-4 1/2) ] ÷ 1/4
=(2/6 + 27/6) ÷ 1/4
=(29/6) ÷ 1/4
=116/6
=19 1/3
=[ (-26) - (-8) ]÷(-3)
=(-18) ÷ (-3)
= -6
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[1/3 - (-4 1/2) ] ÷ 1/4
=(2/6 + 27/6) ÷ 1/4
=(29/6) ÷ 1/4
=116/6
=19 1/3
收錄日期: 2021-04-13 17:58:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070918000051KK04179