[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
個答案係-6,我想知中間點計出黎,姐係要個步驟
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
個答案係+19又3分之1,我想知中間點計出黎,姐係要個步驟
中一數學功課問題,聽日交(10分!!!!!!!!!!!!!!!!)
2007-09-19 5:58 am
回答 (2)
2007-09-19 6:49 am
✔ 最佳答案
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]=[(-26)-(-8)]
= -18÷(-3)
=6
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[(1-3分之2)-(-2分之9)]÷4分之1
=(6分之6-6分之4+6分之29)÷4分之1
=6分之29÷4分之1
=3分之29x2
=+19又3分之1
2007-09-18 22:51:25 補充：
P.S.先乖除...後加減...
參考: me=]
2007-09-19 6:15 am
[(+13)÷(-0.5)-(-16)×(+0.5)]÷[(0.75)×(-4)]
=[-26+32]÷(-3)
=+6÷(-3)
=-2
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[+3分之1-(-4.5)]÷4分之1
=[+3分之1+4.5]÷4分之1
=[+4又6分之5]÷4分之1
=1又24分之5
=[-26+32]÷(-3)
=+6÷(-3)
=-2
[+(1-3分之2)-(-12)×(+8分之3)]÷4分之1
=[+3分之1-(-4.5)]÷4分之1
=[+3分之1+4.5]÷4分之1
=[+4又6分之5]÷4分之1
=1又24分之5
參考: 我
收錄日期: 2021-04-13 13:32:58
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https://hk.answers.yahoo.com/question/index?qid=20070918000051KK04171