(9^x) + [9^(x-1)] - 10 = 0
有冇人可以教我??
中三Maths
2007-09-19 3:47 am
回答 (1)
2007-09-19 3:49 am
✔ 最佳答案
(9^x) +9^(x-1) - 10 = 09^(x-1+1)+9^(x-1)=10
9^(x-1) [ 9+1 ] =10
9^(x-1) x 10=10
9^(x-1)=1
9^(x-1) = 9^0
x-1=0
x=1//
收錄日期: 2021-04-19 22:05:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070918000051KK03146