一條數....幫下我

如果佢哥$8係人地借比佢既 -8
佢用$8去買左隻雞, $9賣比人, 佢有$9, 還$8比人, 佢正反$1
佢再借$9去買反隻雞
$11賣比人, 佢有$11, 佢還反$9比人, 佢正反$2
佢賺$2


如果佢一開始有$8, 用$8去買左隻雞, $9賣比人, 佢有$9
佢去借$1買反隻雞, $11賣比人, 佢有$11, 還反$1比人, 正反$10
$10 - $8 = $2
賺$2

點計都係賺$2

你冇計錯，是earn 2塊。

付出過的錢 $8 + $10 = $18
收回來的錢 $9 + $11 = $22

所以在這兩次買賣中，共得到 $2 的利潤。

我覺得他賺了1元.

8元買入, 9元賣出 : 賺1元.
用10元買入, 把已有的9元再多加1元, 蝕1元.
11元賣出, 賺1元.

1. 成本 8蚊
2. 9蚊賣出, +1蚊
3. 10蚊買回 -1蚊 (打和)
4. 最後11蚊再賣出, 減去成本價8蚊, 即係賺2蚊

I think this person 賺左$0. Because he use $8 to buy a chicken, then he sell it to other people by $9. so he 賺左 $1. But later he use $10 to buy back the chicken, so he didn't 賺anything, and also have a -1. Then he sell that chicken by $11. Although 11-10 is 1. But before, he already sit(cantonese)左$1, so -1-1 is 0.

* I don't know is that right, so don't trust my math at all!!!!

佢只係賺左一蚊....
因為佢用了8蚊去買左...賣得9蚊.....這個時候佢賺左一蚊....
然後：佢又用左10元又買多一隻...這時候虧了1元
最後：佢又以11元賣出...這時候佢又賺左1元...........

你再回想一吓.....其實佢由頭到尾都只賺左1元，又何來的2元呢.....

冇賺過..9蚊賣左比人..即係賺1蚊la ..咁10蚊買番..即係要自已貼多1蚊...依家蝕左1蚊..再11蚊賣番比人..咁咪即係賺番果1蚊..即係冇賺過lo

第一次賣賺左= 9-8 =1
第一次買= 9-10 = -1
第二次賣賺左 = 11-10 = 1
共賺左 = 1-1+1 = 1