Pls help to solve this, with clear steps appreciated!
g(x) = 6x(1-x) for 0<1;
and g(x) =0 elsewhere
Integration
2007-09-17 3:29 pm
回答 (2)
2007-09-17 9:48 pm
✔ 最佳答案
∫g(x)dx [0,1]= ∫ 6x(1-x)dx [0,1]
= ∫ 6x - 6x² dx [0,1]
= [3x² - 2x³][0,1]
= [3(1)² - 2(1)³] - [3(0)² - 2(0)³]
= 1
2007-09-27 5:41 am
The problem have not stated the range for the integration.
而且呢條好眼熟....
而且呢條好眼熟....
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070917000051KK00458