我有兩題5識......希望有人可以幫到我...
1) 12x(x的2次方)+x = 1/6
2)(3x-5)[成個2次方] - (x-1)[都係成個2次方] = 0
好急的~~~
recognizing a quadratic equation(急)
2007-09-17 1:49 am
回答 (1)
2007-09-17 2:02 am
✔ 最佳答案
1)12x(x的2次方)+x = 1/6
72x^2+6x-1 = 0
(12x-1)(6x+1) = 0
x = 1/12 0r - 1/6
2)(3x-5)[成個2次方] - (x-1)[都係成個2次方] = 0
9x^2 -30x +25 - (x^2-2x +1) =0
8x^2+32x+24 = 0
x^2+4x+3 = 0
(x+1)(x+3) = 0
x = -1 0r -3
2007-09-16 18:02:52 補充：
希望幫到你喔!!!
收錄日期: 2021-04-13 13:32:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070916000051KK03700