數學問題!==

6m = 600cm
Let 第一段鐵線的長度 be y cm,
y + (y+1) + (y+2) + ... (y+24) = 600
25y + (1 + 2 + ...+ 24) = 600
25y + (1+24)(24)/2 = 600
25y + 300 = 600
25y = 300
y = 12
Therefore, 第一段鐵線的長度 = 12 cm

let x cm be the first wire's length

x+(x+1)+(x+2)+.......+(x+24)=600

25x+(1+2+3+.......24)=600

25x+300=600

25x=300

x=12

第一段鐵線係１２cm

let x cm be the first wire's length
x+(x+1)+(x+2)+.......+(x+24)=600
25x+(1+2+3+.......24)=600
25x+300=600
25x=300
x=12
第一段鐵線係１２cm

12cm ??

2007-09-15 17:53:34 補充：
coz the first one is X + 0 second one is X + 1 ......... the last one is x + 24 ( x + 0 ) + ( x + 1 ) + ..... + ( x + 24 ) = 60025 * x + ( 1 + 2 +.... + 24 ) = 600 so x = 12 cm

第一段鐵線的長度 = 12
最後段鐵線的長度 = 36