以下有題數唔識做呀~好希望大家幫我~
唔知你地會點計呢？
1)3b^n x 5(b^n)^2 x (6b)^2
我有個答案~好想你地睇下~如果有錯希望大家幫我更正呀~thxs~
1)3b^n x 5(b^n)^2 x (6b)^2
=3b^n x 5b x b^2n x 12b^2
我就係做左咁多就唔識la~希望你地可以幫我~幫到既加5分~
勁急！好想大家幫幫手呀~thxs
2007-09-16 12:42 am
回答 (3)
2007-09-16 12:52 am
✔ 最佳答案
答案---3 b^n*5b^2n*36b^2 = 540b^(n+2n+2)
=540b^(3n+2)
2007-09-15 16:59:02 補充：
你的答案有兩部份錯了(1)5(b^n)^2 = 5x (b^2n)不是等如5b x b^2n (2)(6b)^2= 6^2x b^2= 36b^2 不是等如12b^2
參考: me
2007-09-16 12:54 am
1)3b^n x 5(b^n)^2 x (6b)^2
=3b^n x 5b x b^2n x 36b^2
=3b^n x 5b x b^2n x 36b^2
2007-09-16 12:53 am
1. 3b^n x 5(b^n)^2 x (6b)^2
=3b^n x 5(b^2n) x 36(b^2)
= 3x5x36 x[(b^n x (b^2n) x (b^2)]
= 540 x [b^(n+2n+2)]
=540b^(2+3n)
=3b^n x 5(b^2n) x 36(b^2)
= 3x5x36 x[(b^n x (b^2n) x (b^2)]
= 540 x [b^(n+2n+2)]
=540b^(2+3n)
收錄日期: 2021-04-13 18:25:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070915000051KK03238