a. maths 問題

The proposition S(n) of
‘1+3+5+...+(2n-1)=n^2，
is proved to be true for all positive integers n as follows:
when n=1
L.H.S.2(1) - 1 = 1
RHS=1^2 = 1
∴ L.H.S = R.H.S
∴S(1) is true.
Assume S(k) is true
i.e.,1 + 3 + 5 + ... + (2k - 1) = k^2
when n=k+1
L.H.S.
=1 + 3 + 5 + ... + (2k - 1) +(2k+1)
=k^2+(2k+1)
=(k+1)^2
=R.H.S.
∴ S (k + 1)is true
By the principle of Mathematical Induction, P (n) is true for all natural numbers n.

你條式好似錯左wor...
當n=1時的確係成立
但係你試下代n=2...就唔成立喇
可能我唔識做啦....