問
要有式
(-3)-(-2)(+3)-(-3)(-4)(-5)=
有向數.(10)
2007-09-15 7:36 pm
回答 (3)
2007-09-15 7:41 pm
✔ 最佳答案
(-3)-(-2)(+3)-(-3)(-4)(-5) =(-3)-(-2x3)-(-3x4x5) =(-3)-(-6)-(-60) =-3+6+60 = 63 ==
2007-09-15 8:39 pm
(-3)-(-2)(+3)-(-3)(-4)(-5)
=(-3)-(-6)-(-60)
=63
[(+3)-(-4)(-5)]
------------------
[(-4)(-3)]
=(+3)-(+20)
=(+3)-20
=(-17)
=(-3)-(-6)-(-60)
=63
[(+3)-(-4)(-5)]
------------------
[(-4)(-3)]
=(+3)-(+20)
=(+3)-20
=(-17)
參考: me
2007-09-15 7:40 pm
(-3)-(-2)(+3)-(-3)(-4)(-5)
=(-3)-(-6)-(-60)
=63~~~
=(-3)-(-6)-(-60)
=63~~~
收錄日期: 2021-04-13 18:52:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070915000051KK01383