有向數.(10)

🎓 學業台小學及中學教育

[匿名]

2007-09-15 7:36 pm

問
要有式
(-3)-(-2)(+3)-(-3)(-4)(-5)=

回答 (3)

猁好嗎

2007-09-15 7:41 pm

✔ 最佳答案

(-3)-(-2)(+3)-(-3)(-4)(-5) =(-3)-(-2x3)-(-3x4x5) =(-3)-(-6)-(-60) =-3+6+60 = 63　==

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Betsy

2007-09-15 8:39 pm

(-3)-(-2)(+3)-(-3)(-4)(-5)
=(-3)-(-6)-(-60)
=63

[(+3)-(-4)(-5)]
------------------
[(-4)(-3)]

=(+3)-(+20)
=(+3)-20
=(-17)

參考: me

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路人甲

2007-09-15 7:40 pm

(-3)-(-2)(+3)-(-3)(-4)(-5)
=(-3)-(-6)-(-60)
=63~~~

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