maths一條-----"折舊率"

👨🏻‍🏫 學術台數學

Tim

2007-09-15 6:32 am

maths一條-----"折舊率"

$2000 x (1-r %)^2 = 1805
r點計出黎...

我要step..thx

更新1:

samuel19871 所答的答案錯誤................................!!

更新2:

p3b11 其實個ans is 5...... 但,我唔係好明你計咩...><" 我中三的... 好似有d野我未睇過....so...唔明

回答 (3)

Crystal

2007-09-15 6:54 am

(1-r %)^2 = 0.9025

1-r%=0.95

1-r% = 95%

r = 5

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tsz chun

2007-09-15 6:49 am

2000x(1-r)x(1-r)=1805
2000x(1-2r+r^2)=1805
r^2-2r+1=361/400
400r^2-800r+39=0
r=(800士√(-800)^2-4x400x39)/2x400
r=1.95(rejected) or 0.05
so r is 5%

2007-09-14 22:51:37 補充：
r=1.95 not 0.05so r=195%

參考: me

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[匿名]

2007-09-15 6:42 am

(1-r%)^2=1805/2000

1-r%=(1805/2000)^1/2

r%=1-(1805/2000)^1/2//

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