各位知識朋友 , 入黎幫我手 ar !!!
我有幾條數學問題唔識 , 幫手解答 ar( 數學F.1 )!!!!!!!!!!!!!!!( 要步驟 )
1.(a)(+6)×［(+2)-(-3)］
(b)(-12)×［(-11)-(-14)］
(c)(-12)(-11) - (-12)(-14)
(d)(+7)(-4) - (+3)(-4)
(e)［(-7)-(-3)］×(-6)
(f)(-7)(-6) - (-3)(-6)
各位知識朋友 , 入黎幫我手 ar !!! ( 數學F.1 ) (8)
2007-09-15 3:27 am
回答 (4)
2007-09-15 3:33 am
✔ 最佳答案
1.(a)(+6)×［(+2)-(-3)］=6×(+2+3)
=6×5
=30
(b)(-12)×［(-11)-(-14)］
=-12×(-11+14)
=-12×3
=-36
(c)(-12)(-11) - (-12)(-14)
=131-168
=-37
(d)(+7)(-4) - (+3)(-4)
=-28-(-12)
=-28+12
=-16
(e)［(-7)-(-3)］×(-6)
=(-7+3)×(-6)
=-4×(-6)
=24
(f)(-7)(-6) - (-3)(-6)
=42-18
=24
2007-09-14 19:34:44 補充：
應該係咁先啱:(c)(-12)(-11) - (-12)(-14)=132-168=-36
2007-09-15 3:37 am
1a +6 * (+2--3)
=+6 x -1
=-6
b (-12)×［(-11)-(-14)］
= -12 x 3
=-36
c (-12)(-11) - (-12)(-14)
= 132 - 168
= -36
d(+7)(-4) - (+3)(-4)
= -28 - -12
= -26
e ［(-7)-(-3)］×(-6)
=-4 x -6
=24
f (-7)(-6) - (-3)(-6)
=48 - 18
=30
=+6 x -1
=-6
b (-12)×［(-11)-(-14)］
= -12 x 3
=-36
c (-12)(-11) - (-12)(-14)
= 132 - 168
= -36
d(+7)(-4) - (+3)(-4)
= -28 - -12
= -26
e ［(-7)-(-3)］×(-6)
=-4 x -6
=24
f (-7)(-6) - (-3)(-6)
=48 - 18
=30
參考: me
2007-09-15 3:35 am
1.(a) (+6) × ［(+2)-(-3)］
= 6 (+5) = 30
(b)(-12)×［(-11)-(-14)］
=(-12)(+3)=-36
(c)(-12)(-11) - (-12)(-14)
=132-168
=-36
(d)(+7)(-4) - (+3)(-4)
=-28+12
=-16
(e)［(-7)-(-3)］×(-6)
=(-4)(-6)
=24
(f)(-7)(-6) - (-3)(-6)
=42-18
=24
= 6 (+5) = 30
(b)(-12)×［(-11)-(-14)］
=(-12)(+3)=-36
(c)(-12)(-11) - (-12)(-14)
=132-168
=-36
(d)(+7)(-4) - (+3)(-4)
=-28+12
=-16
(e)［(-7)-(-3)］×(-6)
=(-4)(-6)
=24
(f)(-7)(-6) - (-3)(-6)
=42-18
=24
參考: me
2007-09-15 3:31 am
1.(a)(+6)×［(+2)-(-3)］=6(5)=30
(b)(-12)×［(-11)-(-14)］=(-12)(3)=-36
(c)(-12)(-11) - (-12)(-14)=132-168=-36
(d)(+7)(-4) - (+3)(-4)=-28+12=-16
(e)［(-7)-(-3)］×(-6)=(-4)(-6)=24
(f)(-7)(-6) - (-3)(-6) =42-18=24
(b)(-12)×［(-11)-(-14)］=(-12)(3)=-36
(c)(-12)(-11) - (-12)(-14)=132-168=-36
(d)(+7)(-4) - (+3)(-4)=-28+12=-16
(e)［(-7)-(-3)］×(-6)=(-4)(-6)=24
(f)(-7)(-6) - (-3)(-6) =42-18=24
收錄日期: 2021-04-13 17:12:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070914000051KK02827