開學了 我上到中三 得一條 整數指數定律 的數學題唔知點計出來 幫幫下啦

2^(n+1) / 8^n
= 2^(n+1) / 2^(3n)
= 2^(n+1) * 2^(-3n)
= 2^(n+1 -3n)
=2^(1-2n)
= (2^-(2n-1))
=(1/2)^(2n-1)

2^(n+1) / 8^n

= 2^(n+1) / 2^(3n)

= 1/2^-(n+1) * 2^(3n)

= 1/2^(-n-1+3n)

=1/2^(2n-1)

8的n次方 = (2的3次方)的n次方=2的3n次方

2的(n+1)次方 除 8的n次方= 2的(n+1)次方 除 2的3n次方
= 2的(n+1-3n)次方
= 2的(-2n+1)次方
= 2的(-1)(2n-1)次方
= 1/2 的(2n-1)次方

(2^n+1)/8^n
= (2^n+1)/(2^3)^n
= (2^n+1)/(2^3n)
= 2^(n+1-3n)
= 2(-2n+1)
= 1/2^(2n-1)