中一數學問題!!!!!!!!!!!!!!!!!!!!!!!!!!!!(10分)

2007-09-14 3:36 am
(-15)÷[4(-2)-(5)]
呢題數既答案係+5
我想知中間係點計出黎-.-

(+6)×(-10) +(3又2分之1)
呢題數既答案係+17又7分之1
我想知中間係點計出黎-.-

(-4分之7)×[(-5)÷(-16分之1)]
呢題數既答案係-140
我想知中間係點計出黎-.-

回答 (6)

2007-09-14 3:46 am
✔ 最佳答案
(-15)÷[4(-2)-(5)]
=(-15)÷(4-2-5)
=(-15)÷(-3)
=+5 【因為--得正】

(+6)×(-10) +(3又2分之1)
=(-60) +(3又2分之1) 【因為--得正】
=-56又2分之1 【不是+17又7分之1】


(-4分之7)×[(-5)÷(-16分之1)]
=(-4分之7)×[(-5)*(-16)]
=(-4分之7)×(80)
=-140

2007-09-14 22:07:13 補充:
第二題( 6)×(-10) (-3又2分之1) =(-60) -3又2分之1=-63又2分之1 【都不是 17又7分之1】
2007-09-14 4:06 am
1) (-15)÷[4(-2)-(5)]
=(-15)÷(-3)
=5

2) 你係咪打錯問題??
(+6)×(-10)+(3又2分之1)
=(-60)+(3又2分之1)
=(-56又2分之1)
個問題係咪應該係咁??
(+6)×(-10)÷(3又2分之1)
=(-60)×(7分之2)
=17又7分之1

3) (-4分之7)×[(-5)÷(-16分之1)]
= (-4分之7)×[(-5)×(-16)]
=(-4分之7)×80
=140
參考: myself
2007-09-14 3:54 am
請問你第1&第2題是否看錯正負號?
而第3題
(-4分之7)×[(-5)÷(-16分之1)]
=(-4分之7)×[(-16分之80)÷(-16分之1)]
=(-4分之7)×[(-16分之80)X(-16)]
=(-4分之7)×(80)
=-140
2007-09-14 3:52 am
(-15)÷[4(-2)-(5)]
= -15÷(4-2-5)
= -15÷-3
=+5


(**sor!!!我only識做lee條....other唔識做.....不過我希望我可以幫到你第1條啦~)

sor!!!
參考: myself
2007-09-14 3:48 am
(-15)÷[4-2-5]
=(-15)÷[-3]
=5

(+6)×(-10) +(3又2分之1)
=-60 + 7/2
=-120/2 +7/2
=(7-120)/2
=-113/2
so I don't know is your question is wrong.........

(-7/4 )×[(-5)÷(-1/16)]
=(-7/4 )×[-5×-16]
=(-7/4 )×[80]
=-560/4
=-140
2007-09-14 3:47 am
(-15)÷[4(-2)-(5)]
=(-15)/(4-2-5)
=(-15)/(-3)
=5


(+6)×(-10) +(3又1/2)
=(-60)+(3 1/2)
= -56又1/2
唔係=17又7分之1

(-7/4) x[(-5) / (1/-16)]
= (-7/4) x80
=-140


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