1. Given that triangleABC ~ triangleDEF.If angleE=angle F = 72度, DE=8 , EF = 5 and BC=12.5, find
(a) angle A
(b)AB
2. Find a number k that can be used to eliminate the fractionns in the equation c-5 over 6 and +3 = 2- c over 8 by multiplying it on both sides.
steps plz..
f.1 maths
2007-09-13 10:55 pm
回答 (2)
2007-09-14 5:59 am
✔ 最佳答案
1(a)∵triangleABC~triangleDEF
∴angleE=angleF
angleD+angleE+angleF=180°(angle sum of triangle)
angleD=180°-angleE-angleF
angleD=180°-72°-72°
angleD=36°
angleA=angleD
angleA=36°
(b)
∵triangleABC~triangleDEF
∴AB=DE
AB=8
2
the answer should be the L.C.M. of 6 and 8
L.C.M. of 6,8=24
參考: MYSELF+MY DAD:P
2007-09-14 12:29 am
1a)由於 triangleABC ~ triangleDEF
so angle E=angle B，angleF=angleC
angleB+ angleC+angleA =180 (angle sum of triangle)
angleA=36
1b)由於 triangleABC ~ triangleDEF
so 5/12.5=8/AB
use 交叉相X
THEN AB=20
我唔係太清楚第二題係想問咩?
so angle E=angle B，angleF=angleC
angleB+ angleC+angleA =180 (angle sum of triangle)
angleA=36
1b)由於 triangleABC ~ triangleDEF
so 5/12.5=8/AB
use 交叉相X
THEN AB=20
我唔係太清楚第二題係想問咩?
參考: MYSELF
收錄日期: 2021-05-02 21:57:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070913000051KK01288