3(3x-4)2次-11(3x-4)+10=0
列式!!!!
中4附數....急!!
2007-09-13 5:34 am
回答 (2)
2007-09-13 5:43 am
✔ 最佳答案
9)3(3x – 4)2 – 11(3x – 4) + 10 = 0[3(3x – 4) – 5] [(3x – 4) – 2] = 0
[9x – 12 – 5] [3x – 4 – 2] = 0
[9x – 17] [3x – 6] = 0
x = 17/9 或 x = 6/3 = 2
2007-09-13 5:44 am
Let Y = 3x - 4
3Y^2 - 11Y + 10 = 0
(3Y-5)(Y-2) = 0
Y = 5/3 or Y = 2
If Y = 5/3,
3x - 4 = 5/3
3x = 5/3 + 4 = 17/3
x = 17/9
If Y = 2,
3x - 4 = 2
3x = 6
x = 2
3Y^2 - 11Y + 10 = 0
(3Y-5)(Y-2) = 0
Y = 5/3 or Y = 2
If Y = 5/3,
3x - 4 = 5/3
3x = 5/3 + 4 = 17/3
x = 17/9
If Y = 2,
3x - 4 = 2
3x = 6
x = 2
收錄日期: 2021-04-13 13:26:47
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