中二數學(~急~)

1.3(2x+A)≡2(3x+B)
6x+3A ≡ 6x+2B
3A ≡ 2B
therefore, A=2 B=3

2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y+A≡By+5
therefore, A=5 B=8

3.(x+4)(x-3)=x(x+1)-12

LHS = (x+4)(x-3)

=X(2次方) + X - 12

RHS = x(x+1)-12

= X(2次方) + X -12

因為左手面和右手面的方程式相等
所以 (x+4)(x-3)≡x(x+1)-12

唔知啱唔啱,唔啱唔好"炳"我 =0=

1. 3( 2x+A) ≡2(3x+B)
6x+ 3A≡6x+2B
3A≡2B
A≡2/3 B

2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y≡By
-4+A≡1
A≡5
( 我吾得哩題嘅格式可能吾係咁寫 )

3. (x+4)(x-3)=x(x+1)-12
LHS= (x+4)(x-3)
= x2+x-12
RHS= x(x+1)-12
= x2+x-12
(x2 = x 既 ２ 次方, 哩度打吾到 )

1) 3(2x+A)≡2(3x+B)
6x + 3A≡6x + 2B
3A≡2B
A≡2 & B=3

2) 4(2y-1)+A≡By +1
8y - 4 + A≡By + 1
8y + (A-4)≡By + 1
B=8 & A-4=1
B=8 & A=5

3) (x+4)(x-3)≡x^2 + x - 12
≡x(x+1) -12

1. 6x+3A≡6x+2B
A=2/3B
B=4/3A
2. 8y-4+A≡By+1
A=5
B=8
3. LHS=X的二次-3x+4x-12
=X的二次+X-12
RHS=X的二次+X-12
LHS=RHS 所以(x+4)(x-3)≡x(x+1)-12

1 6X+3A≡6x+2B
3A=2B
A/B=2/3
A=2 B=3
2 4(2y-1)+A≡By+1
8y-4+A=By+1
B=8 -4+A=1
A=5
3.(x+4)(x-3)=x(x+1)-12
RHS=x^2+x-12
=(x+4)(x-3)
=LHS
希望幫到你

証明恆等式

3.(x+4)(x-3)=x(x+1)-12

証:右=x^2+x-12
=(x+4)(x-3)
=左 (得証)