恆等式
求A和B的值
1.3(2x+A)≡2(3x+B)
2.4(2y-1)+A≡By+1
証明恆等式
3.(x+4)(x-3)=x(x+1)-12
中二數學(~急~)
2007-09-13 4:45 am
回答 (6)
2007-09-13 5:06 am
1.3(2x+A)≡2(3x+B)
6x+3A ≡ 6x+2B
3A ≡ 2B
therefore, A=2 B=3
2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y+A≡By+5
therefore, A=5 B=8
3.(x+4)(x-3)=x(x+1)-12
LHS = (x+4)(x-3)
=X(2次方) + X - 12
RHS = x(x+1)-12
= X(2次方) + X -12
因為左手面和右手面的方程式相等
所以 (x+4)(x-3)≡x(x+1)-12
唔知啱唔啱,唔啱唔好"炳"我 =0=
6x+3A ≡ 6x+2B
3A ≡ 2B
therefore, A=2 B=3
2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y+A≡By+5
therefore, A=5 B=8
3.(x+4)(x-3)=x(x+1)-12
LHS = (x+4)(x-3)
=X(2次方) + X - 12
RHS = x(x+1)-12
= X(2次方) + X -12
因為左手面和右手面的方程式相等
所以 (x+4)(x-3)≡x(x+1)-12
唔知啱唔啱,唔啱唔好"炳"我 =0=
2007-09-13 5:01 am
1. 3( 2x+A) ≡2(3x+B)
6x+ 3A≡6x+2B
3A≡2B
A≡2/3 B
2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y≡By
-4+A≡1
A≡5
( 我吾得哩題嘅格式可能吾係咁寫 )
3. (x+4)(x-3)=x(x+1)-12
LHS= (x+4)(x-3)
= x2+x-12
RHS= x(x+1)-12
= x2+x-12
(x2 = x 既 ２ 次方, 哩度打吾到 )
6x+ 3A≡6x+2B
3A≡2B
A≡2/3 B
2.4(2y-1)+A≡By+1
8y-4+A≡By+1
8y≡By
-4+A≡1
A≡5
( 我吾得哩題嘅格式可能吾係咁寫 )
3. (x+4)(x-3)=x(x+1)-12
LHS= (x+4)(x-3)
= x2+x-12
RHS= x(x+1)-12
= x2+x-12
(x2 = x 既 ２ 次方, 哩度打吾到 )
參考: 我上年讀完=)
2007-09-13 4:59 am
1) 3(2x+A)≡2(3x+B)
6x + 3A≡6x + 2B
3A≡2B
A≡2 & B=3
2) 4(2y-1)+A≡By +1
8y - 4 + A≡By + 1
8y + (A-4)≡By + 1
B=8 & A-4=1
B=8 & A=5
3) (x+4)(x-3)≡x^2 + x - 12
≡x(x+1) -12
6x + 3A≡6x + 2B
3A≡2B
A≡2 & B=3
2) 4(2y-1)+A≡By +1
8y - 4 + A≡By + 1
8y + (A-4)≡By + 1
B=8 & A-4=1
B=8 & A=5
3) (x+4)(x-3)≡x^2 + x - 12
≡x(x+1) -12
2007-09-13 4:56 am
1. 6x+3A≡6x+2B
A=2/3B
B=4/3A
2. 8y-4+A≡By+1
A=5
B=8
3. LHS=X的二次-3x+4x-12
=X的二次+X-12
RHS=X的二次+X-12
LHS=RHS 所以(x+4)(x-3)≡x(x+1)-12
A=2/3B
B=4/3A
2. 8y-4+A≡By+1
A=5
B=8
3. LHS=X的二次-3x+4x-12
=X的二次+X-12
RHS=X的二次+X-12
LHS=RHS 所以(x+4)(x-3)≡x(x+1)-12
2007-09-13 4:54 am
1 6X+3A≡6x+2B
3A=2B
A/B=2/3
A=2 B=3
2 4(2y-1)+A≡By+1
8y-4+A=By+1
B=8 -4+A=1
A=5
3.(x+4)(x-3)=x(x+1)-12
RHS=x^2+x-12
=(x+4)(x-3)
=LHS
希望幫到你
3A=2B
A/B=2/3
A=2 B=3
2 4(2y-1)+A≡By+1
8y-4+A=By+1
B=8 -4+A=1
A=5
3.(x+4)(x-3)=x(x+1)-12
RHS=x^2+x-12
=(x+4)(x-3)
=LHS
希望幫到你
參考: me
2007-09-13 4:53 am
証明恆等式
3.(x+4)(x-3)=x(x+1)-12
証:右=x^2+x-12
=(x+4)(x-3)
=左 (得証)
3.(x+4)(x-3)=x(x+1)-12
証:右=x^2+x-12
=(x+4)(x-3)
=左 (得証)
收錄日期: 2021-04-13 13:26:47
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