2題因式分解

2007-09-13 4:05 am
2m^2(m^2 - 25n^2) + 50n^2(25n^2 - m^2)

(3X^2 + 2X - 8)^2 - (x^2 -2X - 8)^2


要步驟 thx....

回答 (3)

✔ 最佳答案
2m2(m2 - 25n2) + 50n2(25n2 - m2)
=2(m2 - 25n2)(m2 -25n2)
=2(m-5n)2(m+5n)2

(3x2 + 2x - 8)2 - (x2 -2x - 8)2
=[(3x2 + 2x - 8)- (x2 -2x - 8)] [(3x2 + 2x - 8)+ (x2 -2x - 8)]
=(3x2 + 2x - 8- x2+2x+ 8) (3x2 + 2x – 8+x2 -2x - 8)
=(2x2 +4x)(4x2-16)
=8x(x+2)(x2 -4)
=8x(x+2)2 (x-2)
2007-09-13 4:27 am
2m^2(m^2 - 25n^2) + 50n^2(25n^2 - m^2)
=2m^2(m^2 - 25n^2) - 50n^2( m^2 - 25n^2)
=(2m^2 - 50n^2)( m^2 - 25n^2)


(3X^2 + 2X - 8)^2 - (x^2 -2X - 8)^2
=(3x^2 + 2x - 8 + x^2 - 2x - 8)(3x^2 + 2x - 8 - x^2 + 2x + 8)
=(4x^2 - 16)(2x^2 + 4x)
=2(2x^2 - 8)(x^2 + 2x)
參考: myself
2007-09-13 4:27 am
2m^2(m^2 - 25n^2) + 50n^2(25n^2 - m^2)
=2(m^2 - 25n^2)(m^2 - 25n^2)
=2(m^2 - 25n^2)^2

(3X^2 + 2X - 8)^2 - (X^2 -2X - 8)^2
=[(3X - 4)(X - 2)]^2 - [(X - 4)(X - 2)]^2
=[(3X - 4)^2 -(X - 4)^2](X - 2)^2
=2X(4X - 8)(X + 2)^2


收錄日期: 2021-04-25 21:56:52
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