solve x
Q1 2x^2-15x-8=0
Q2 4x^2-13x-12=0
請用cross method，並寫清楚步驟！thz
maths maths
2007-09-12 1:26 am
回答 (2)
2007-09-12 1:39 am
Q1 x -8
2x 1
----------------
-16x + x = - 15x
( x - 8 ) ( 2x + 1) = 0
so x = 8 or - 1/2
Q2 x -4
4x 3
-----------------
-16x + 3x = -13x
( x - 4 ) ( 4x + 3) = 0
so x = 4 or - 3/4
2x 1
----------------
-16x + x = - 15x
( x - 8 ) ( 2x + 1) = 0
so x = 8 or - 1/2
Q2 x -4
4x 3
-----------------
-16x + 3x = -13x
( x - 4 ) ( 4x + 3) = 0
so x = 4 or - 3/4
2007-09-12 1:31 am
Q1 2x^2-15x-8=0
(2x+1)(x-8)=0
x=8 or -1/2 ~~
Q2 4x^2-13x-12=0
(4x+3)(x-4)=0
x=4 or -3/4 ~~
(2x+1)(x-8)=0
x=8 or -1/2 ~~
Q2 4x^2-13x-12=0
(4x+3)(x-4)=0
x=4 or -3/4 ~~
收錄日期: 2021-04-13 18:53:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070911000051KK02140