多項式(pure maths)
回答 (2)
2007-09-11 5:48 am
✔ 最佳答案
x^5+x-2=(x-1)(x^4+x^3+x^2+x+2)
2007-09-11 5:53 am
f(x-1)=1－－－－唔知係咪
f(x)=x^5+x-2
f(1)=1^5+1-2
= 1+(-1)
=0
I try my best~~!!
f(x)=x^5+x-2
f(1)=1^5+1-2
= 1+(-1)
=0
I try my best~~!!
收錄日期: 2021-04-13 13:25:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070910000051KK04285