兩條數學題
1 ) 3^2n-1 +4(3^2n) / 2(3^2n+1)
2) 2^2n+1 +7(2^n) / 4(2^n)
唔該!!
maths題...10點
2007-09-10 6:07 am
回答 (1)
2007-09-10 6:22 am
✔ 最佳答案
a)[32n-1+4(32n)]/2[32n+1]= 32n‧3-1 + 4(32n) / 2(3)(32n)
= 32n(1/3+4) / (32n)(6)
= (13/3) / 6
= 13/18
b)[2n+1+7(2n)]/4(2n)
= 2n‧2n‧2 + 7(2n) / 4(2n)
= 2n(2‧2n + 7)/4(2n)
= (2‧2n + 7) / 4
收錄日期: 2021-04-25 15:37:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070909000051KK05262