關於數學一條數

2007-09-10 4:21 am
x-1/x+1 - x+1/x-1

= (x-1)(x-1)/(x+1)(x-1) - (x+1)(x+1)/(x+1)(x-1)

最想知跟住點變成咁

= x^2-x-x+1 - x^2-x-x-1 <<重點/(x+1)(x-1)

= -4x/(x+1)(x-1)

個重點果到佢係咪用左cross method先計到

p.s條數係中2的

中2果陣我幾乎係訓堂so唔明

回答 (1)

2007-09-10 4:31 am
✔ 最佳答案
你寫錯step!
唔係 (x-1)(x-1)/(x+1)(x-1) - (x+1)(x+1)/(x+1)(x-1)
應該係: [(x-1)(x-1) - (x+1)(x+1)]/(x+1)(x-1)

分子:
(x-1)(x-1)乘出黎=x^2-x-x+1
(x+1)(x+1)乘出黎=x^2+x+x+1
所以,分子=(x^2-x-x+1)-(x^2+x+x+1)=x^2-x-x+1-x^2-x-x-1=-4x

所以,答案係-4x/(x+1)(x-1)


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