數學問題`

1)2c3．c4/6c2
=2c3+4/6c2
=2c7/6c2
=c7-2/3
=c5/3
根據指數定律am．an = am+n

2) (a2)3(a2)
= a6‧a2
= a6+2
= a8
根據指數定律(am)n = am×n


3) (-3x2y)3
= (-3)3x2×6 y3
= (-3)3 x2×3 y3
= -27x6y3
同理，根據指數定律(am)n = am×n


4)(4e2 /3f)4
= 44e8 /34f4
= 256e8 /81f4
同理，根據指數定律(am)n = am×n


5) 2n+1/2n-1
= 2n+1-(n-1)
= 2n+1-n+1
= 21+1
= 22
= 4
根據指數定律am/an = am-n

1. =c^(3+4-2)/3 = c^5/3
2. (a^2)^3(a^2) = a^6*a^2 = a^(6+2) = a^8
3. (-3x^2y)^3 = -27x^6y^3
4. = 4^4e^8/3^4f^4
= 256e^8/81f^4
5. = 2^[(n+1)-(n-1)]
=2^2 = 4