中四的數學(數與函數)~急...

2007-09-08 6:21 pm
唔識做呀~><
請大家幫下手~

1.(a)展開(2N+1)(2N+3) <=呢條我識計
答案:4N^2+8N+3

(b)己知N是整數。求證 <=呢條唔識計
(i)(2N+1)(2N+3)是奇數。
(ii)(2N+1)(2N+3)+1是4的倍數。

我打埋(a)係唔知同(b)有無關係~

回答 (1)

2007-09-08 6:31 pm
✔ 最佳答案
1(b)
(i)(2N+1)(2N+3)是奇數。
(ii)(2N+1)(2N+3)+1是4的倍數。
因為N是整數,所以2N是偶數,2N+1是奇數,2N+3也是奇數。
(2N+1)(2N+3)=奇數×奇數=奇數

(2N+1)(2N+3)+1
=(4N2+8N+3)+1 [(2N+1)(2N+3)= 4N2+8N+3是1(a)的答案]
=4N2+8N+4
=4(N2+2N+1)
因為N是整數,所以(N2+2N+1) 是整數,4(N2+2N+1)是4的倍數。

很明顯,(a)、(b)有關係。
參考: By CY


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