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更新1:
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一條比較複雜既數學方程
回答 (6)
2007-09-08 5:05 pm
✔ 最佳答案
分3個部份:4x+2/2 = 2x+1
2(4x+2) = 8x+4
4x+2 唔駛轉
成條式變左
2x+1+8x+4+4x+2=60
2x+8x+4x+1+4+2=60
14x+7=60
14x=52
x=52/14
x=3.71(corr.to 3sig.)
2007-09-08 09:06:43 補充：
14x=53x=53/14x=3.79(corr.to 3sig.)打錯左
2007-09-14 9:11 am
[ ( 4x + 2 ) / 2 ] + [ 2 ( 4x + 2 ) ] + ( 4x + 2 ) = 60
( 4x + 2 ) ( 1/2 + 2 + 1 ) = 60
( 7 / 2 ) ( 4x + 2 ) = 60
4x + 2 = 120 / 7
4x = 106 / 7
x = 53 / 14
( 4x + 2 ) ( 1/2 + 2 + 1 ) = 60
( 7 / 2 ) ( 4x + 2 ) = 60
4x + 2 = 120 / 7
4x = 106 / 7
x = 53 / 14
2007-09-12 4:18 am
[(4x+2)/2]+[2(4x+2)]+(4x+2)=60
2x+1+8x+4+4x+2=60
14x=53
x=53/14
2x+1+8x+4+4x+2=60
14x=53
x=53/14
2007-09-08 8:12 pm
[(4x+2)/2]+[2(4x+2)]+(4x+2)=60
(2x + 1) + (8x + 4) + 4x + 2 = 60
2x + 8x + 4x + 1 + 4 + 2 = 60
14x + 7 = 60
14x = 53
x = 3.79 (cor. to 3.sig.fig)
(2x + 1) + (8x + 4) + 4x + 2 = 60
2x + 8x + 4x + 1 + 4 + 2 = 60
14x + 7 = 60
14x = 53
x = 3.79 (cor. to 3.sig.fig)
2007-09-08 6:07 pm
[(4x+2)/2]+[2(4x+2)]+(4x+2)=60
(4x+2)+4(4x+2)+2(4x+2)=120 成條式乘2
4x+2+16x+8+8x+4=120
28x+14=120
28x=106
x=53/14
(4x+2)+4(4x+2)+2(4x+2)=120 成條式乘2
4x+2+16x+8+8x+4=120
28x+14=120
28x=106
x=53/14
2007-09-08 5:12 pm
[(4x+2)/2]+[2(4x+2)]+(4x+2)=60
[(4x+2)/2]+8x+4+4x+2=60
2{[(4x+2)/2]+8x+4+4x+2}=60(2)
4x+2+16x+8+8x+4=120
28x+14=120
28x=106
x=3/11/14
[(4x+2)/2]+8x+4+4x+2=60
2{[(4x+2)/2]+8x+4+4x+2}=60(2)
4x+2+16x+8+8x+4=120
28x+14=120
28x=106
x=3/11/14
參考: 自己計
收錄日期: 2021-04-27 13:35:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070908000051KK00659