請問 x+4y=12
如果-6呢個數代入x 禁y既點樣可以計出黎??
about數學 F.3 2元1次方程`
2007-09-08 2:20 am
回答 (4)
2007-09-08 4:51 am
✔ 最佳答案
x+4y=12-6+4y=12
4y=12+6
4y=18
y=18/4
y=4.5
2007-09-08 2:26 am
(-6 )+ 4y= 12
4y = 18
y = 18 ÷ 4
y = 4.5
2007-09-08 2:26 am
-6+4y=12
4y=12+6
4y=18
y=4.5
4y=12+6
4y=18
y=4.5
2007-09-08 2:23 am
x+4y=12
x = -6
-6 + 4y = 12
4y = 18
y = 18 ÷ 4
y = 4.5
x = -6
-6 + 4y = 12
4y = 18
y = 18 ÷ 4
y = 4.5
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