1. cosΘ = sin32°
2. tan (90°-Θ) = tan35° 分之 1
3. cos^2 37° + cos^2 53°
4. prove that sinΘ cosΘ tan (90°-Θ)
5. tan 60° - tan 30°
--------------------------- x cos 30° + sin 30°
1+ tan 45°
urgent!!! thanks!!!
更新1:
SORRY... 係要搵Θ,同埋要留番個√係answer度
更新2:
√係如有需要先加...
更新3:
SORRY...第4題漏左d野... 4. prove that sinΘ cosΘ tan (90°-Θ) = 1 - cos^2 (90°-Θ) thanks!!
