A maths(2)

2007-09-06 3:45 am
Solve it by completing the square.
1. 5x^2 = 7x -2
2. 2x^2 - 3√2x+2 =0

回答 (3)

2007-09-06 3:52 am
✔ 最佳答案
1. 5x^2 = 7x -2
5x^2-7x+2=0
5x^2-5x-2x+2=0
5x(x-1)-2(x-1)=0
(x-1)(5x-2)=0
(x-1)=0 or (5x-2)=0
x=1 or x=2/5//
2. 2x^2 - 3√2x+2 =0
2x^2-3√2x=-2
x^2-(3/2)√2x=-1
x^2-(3/2)√2x+(3√2/2)^2-(3√2/2)^2=-1
(x-3√2/2)^2=-1+9/2
(x-3√2/2)^2=7/2
x-3√2/2=+/- √(7/2)
x=+/-√(7/2)+3√2/2//

2007-09-06 4:08 am
5x^2=7x-2
5x^2-7x=-2
5(x^2-7/5x)=-2
5(x^2-7/5x+(7/10)^2-(7/10)^2)=-2
5(x^2-7/5x+(7/10)^2)-5(7/10)^2=-2
5(x-7/10)^2=-2+5(7/10)^2
5(x-7/10)^2=45/100
(x-7/10)^2=9/100
(x-7/10)=+(9/100)^1/2 or -(9/100)^1/2
(x-7/10)=+(3/10) or -(3/10)
x=+(3/10)+(7/10) or -(3/10)+(7/10)
x=1 or 4/10 = 0.4

2x^2 - 3√2x+2 =0
2(x^2 - 3/2√2x)=-2
2(x^2 - 3/2√2x+(3/4√2)^2-(3/4√2)^2)=-2
2(x^2 - 3/2√2x+(3/4√2)^2)-2(3/4√2)^2)=-2
2(x^2 - 3/2√2x+(3/4√2)^2)=-2+(3/4√2)^2)
2(x-(3/4√2))^2=9/8
(x-(3/4√2))^2=9/16
(x-(3/4√2))=(9/16)^1/2 or -(9/16)^1/2
(x-(3/4√2))=(3/4) or -(3/4)
x = 3/4+3/4√2 or -3/4+3/4√2
x = 3/4(1+√2 ) or 3/4(√2 -1)
參考: 自己
2007-09-06 3:49 am
1 . 7x-2=5x=5x^2
2 . ???


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