Find the derivatives y=5x^2-3x+4
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Find the derivatives y=5x^2-3x+4
2007-09-05 1:35 am
回答 (2)
2007-09-05 1:42 am
✔ 最佳答案
dy/dx=10x-3d^2y/dx^2=10
2007-09-06 20:27:46 補充：
D constant =0
2009-06-21 1:35 am
y=5x²-3x+4
dy/dx = d(5x²)/dx - d(3x)/dx + d(4)/dx
dy/dx=2(5x) - 3 + 0
=10x-3
d²y/dx= d(10x)/dx - d(3)/dx
=10-0
=10
dy/dx = d(5x²)/dx - d(3x)/dx + d(4)/dx
dy/dx=2(5x) - 3 + 0
=10x-3
d²y/dx= d(10x)/dx - d(3)/dx
=10-0
=10
收錄日期: 2021-04-13 13:18:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070904000051KK02488