solve
(1/x)+(1/y)= 6
(1/x)-(1/y)= -2
x=? y=?
maths
2007-09-03 11:53 pm
回答 (2)
2007-09-03 11:58 pm
✔ 最佳答案
(1/x)+(1/y)= 6------(1)(1/x)-(1/y)= -2--------(2)
(1) + (2)
2/x = 4
x = 1/2
Substitue x = 1/2 into (1)
[1/(1/2)] + (1/y) = 6
2 + (1/y) = 6
1/y = 4
y = 1/4
2007-09-04 12:01 am
(1/x)-(1/y)= -2
(1/x) = (1/y)-2...(1)
Substitute (1/x) = (1/y)-2 into (1/x)+(1/y)= 6
(1/y)-2+(1/y)= 6
2/y = 8
y = 1/4
substitute y = 1/4 into (1)
1/x = 1/(1/4) -2
1/x = 4-2
1/x = 2
x=1/2
(1/x) = (1/y)-2...(1)
Substitute (1/x) = (1/y)-2 into (1/x)+(1/y)= 6
(1/y)-2+(1/y)= 6
2/y = 8
y = 1/4
substitute y = 1/4 into (1)
1/x = 1/(1/4) -2
1/x = 4-2
1/x = 2
x=1/2
收錄日期: 2021-04-13 13:16:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070903000051KK02151