解分式方程

2007-09-03 9:12 pm
1/(x-5) + 1/(x+2) = 1/(x-4) + 1/(x+1)

回答 (3)

2007-09-03 9:31 pm
✔ 最佳答案
如下:


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參考: me
2007-09-03 11:24 pm
(x-4+x+1)/((x-5)(x+2))=(x-5+x+2)/((x-4)(x+1))
(2x-3)/((x-5)(x+2))=(2x-3)/((x-4)(x+1))
(x-5)(x+2)=(x-4)(x+1)
x^2-3x-10=x^2-3x-1
x=3
參考: me
2007-09-03 9:28 pm
(x + 2 + x - 5)/((x-5)(x+2)) = (x+1 + x- 4)/((x-4)(x+1))
(2x -3)/((x-5)(x+2)) = (2x -3)/((x-4)(x+1))
(2x -3)((x-4)(x+1)) = (2x -3)((x-5)(x+2))
(2x - 3)((x-4)(x+1) - (x-5)(x+2)) = 0
(2x - 3)(6) = 0
x = 3/2


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