✔ 最佳答案
正負數:
當A=(-2),B=3和c=(-1)時,求下例各代數式的值
(A) abc
=(-2)x(3)x(-1)
= 6
解釋:
正負數乘除 首先計左數字 吾好理d正負號先 等如 2 x3 x 1=6
之後就計正負號 條式 (-2)x(+3) =(-)x(+) = 負正得負 = -6
(-6)x(-1) = 負負得正 = +6 / 6
(B) -a-(-b)+c
= -(-2)-(-3)+(-1)
= 2+3-1
=4
解釋:
-(-2) = 將出面個負號乘去入面個負號 = 負負得正 =+2
-(-3) = 將出面個負號乘去入面個負號 = 負負得正 =+3
+(-1)= 將出面個正號乘去入面個負號 = 正負得負 = -1
(C) 2a-b-c
= 2x (-2) -3-(-1)
= -4 -3+1
=-6
解釋:
2X(-2) = 正2 x 負2 = 正負得負 = -4
-(-1) = 將出面個負號乘以入要個負號 = 負負得正 = +1
(D)a+b
——
c
= (-2)+3
_____
-1
= -2+3
____
-1
= +1
__
-1
= -1
解釋:
(-2)+3 = 刪括號 = -2+3 = +1
+1
___ = 正負得負 = -1
-1