數學~急!

若序偶(a,4)和(-2,b)均滿足方程 2X-3Y=8

1.求a的值.

2.求b的值.


WHEN X=a Y=4
2X-3Y=8
2a-3(4)=8
2a-12=8
2a=8+12
2a=20
a=10//


WHEN X=-2 Y=b
2X-3Y=8
2(-2)-3b=8
-4-3b=8
-3b=8+4
-3b=12
b=-4//

代a不代b之後代b不代a就計到

Put (a,4) into 2X-3Y=8
2a-3(4) = 8
2a-12 = 8
2a = 20
a=10
Put (-2,b) into 2X-3Y = 8
2 (-2) - 3b = 8
-4 -3b = 8
-3b = 12
b = -4

由於(a,4)和(-2,b)均滿足方程 2X-3Y=8
所以: 2a - 3(4)=8
2a - 12=8
2a=20
a =10

2(-2) - 3b = 8
-4 - 3b = 8
-3b = 12
b = -4

a=10
b= - 4