若序偶(a,4)和(-2,b)均滿足方程 2X-3Y=8
1.求a的值.
2.求b的值.
數學~急!
2007-09-02 6:24 pm
回答 (5)
2007-09-02 6:30 pm
✔ 最佳答案
若序偶(a,4)和(-2,b)均滿足方程 2X-3Y=81.求a的值.
2.求b的值.
WHEN X=a Y=4
2X-3Y=8
2a-3(4)=8
2a-12=8
2a=8+12
2a=20
a=10//
WHEN X=-2 Y=b
2X-3Y=8
2(-2)-3b=8
-4-3b=8
-3b=8+4
-3b=12
b=-4//
2007-09-03 3:44 am
代a不代b之後代b不代a就計到
2007-09-02 6:33 pm
Put (a,4) into 2X-3Y=8
2a-3(4) = 8
2a-12 = 8
2a = 20
a=10
Put (-2,b) into 2X-3Y = 8
2 (-2) - 3b = 8
-4 -3b = 8
-3b = 12
b = -4
2a-3(4) = 8
2a-12 = 8
2a = 20
a=10
Put (-2,b) into 2X-3Y = 8
2 (-2) - 3b = 8
-4 -3b = 8
-3b = 12
b = -4
參考: me
2007-09-02 6:32 pm
由於(a,4)和(-2,b)均滿足方程 2X-3Y=8
所以: 2a - 3(4)=8
2a - 12=8
2a=20
a =10
2(-2) - 3b = 8
-4 - 3b = 8
-3b = 12
b = -4
所以: 2a - 3(4)=8
2a - 12=8
2a=20
a =10
2(-2) - 3b = 8
-4 - 3b = 8
-3b = 12
b = -4
2007-09-02 6:31 pm
a=10
b= - 4
b= - 4
收錄日期: 2021-04-13 18:29:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070902000051KK00962