math...答我一題都好...好趕

2007-09-02 12:57 am
解方程

1. 2[3x(x-2)]=3[2x(x-1)]+12

2. 2(x-2)-3(x-1)-5=3-5(x+1)

3. 3over2(x+1)-5over6=-1over3(x-2)

4. 一個數字的五倍較該數字的三倍大4.求該數字
 設x為該數字

回答 (2)

2007-09-02 1:11 am
✔ 最佳答案
1.2[3x(x-2)]=3[2x(x-1)]+12
6x^2-12x=6x^2-6x+12
-6x=12
x=-2
2. 2(x-2)-3(x-1)-5=3-5(x+1)
2x-4-3x+3-5=3-5x-5
-x-6=-5x-2
4x=4
x=1
3.3over2(x+1)-5over6=-1over3(x-2)
9(x+1)-5=-2(x-2)
9x+4=-2x+4
x=0
4.let x be the required number
5x-4=3x
x=2
therefore the required number is 2.

唔知有冇錯你自己驗算下
2007-09-04 2:05 am
講得好


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