1. Ann had $100. She used part of her money to buy 7 ceramic cats, in which 3 of them are more expensive than the rest by $3. If she had $7 left, how much do the two types of ceramic cat cost?
2. The cost of tea A is $30 per kg, the cost of tea B is $20 per kg. If w kg of tea A and (w+1) kg of tea B are mixed together, and the cost of the mixed tea is $24 per kg. Find w.
F.1 升 F.2 ~~數學 ＊急＊ (詳細d,,唔該) (5分1題!!)
2007-09-01 8:53 pm
回答 (2)
2007-09-01 9:12 pm
✔ 最佳答案
1)LET E BE THE COST OF ONE MORE EXPENSIVE CAT ANDC BE THE COST OF ONE CHEAPER CAT,
E-C =3
E=3+C -------------(1)
4C+3E=100-7
4C+3E=93--------(2)
SUB. (1)INTO(2),
4C+3(3+C)=93
4C+9+3C=93
7C=84
C=12
SUB. C=12 INTO (1)
E=3+12
E=15
THEREFORE, ONE MORE EXPENSIVE CAT COST $15
AND ONE CHEAPER CATCOST$12
2) 30w+20(w+1)=24
30w+20w+20=24
50w=4
w=0.08
2007-09-01 9:12 pm
１． ｌｅｔ ｔｈｅ ＄ ｏｆ ｔｈｅ ｌｏｗ ｐｒｉｃｅ ｃｅｒａｍｉｃ ｃａｔ ｂｅ ｎ
（１００－７）＝９３
４ｎ＋（３ｎ＋３）＝７ｎ＋９
９３＝７ｎ＋９
ｎ＝１２
２．３０ｗ＋２０（ｗ＋１）／ｗ＋ｗ＋１＝２４
５０ｗ＋２０ ＝４８ｗ＋２４
２ｗ ＝４
ｗ ＝２
３．ｌｅｔ ｔｈｅ ｏｒｉｇｉｎａｌ ｎｕｍｂｅｒ ｏｆ ｔｈｅ ｇｌａｓｓ ｂｅａｄｓ ｂｅ ｎ
ｎ－（１／２＋１／６＋１／７）ｎ＝１６
ｎ－（３４／４２）ｎ ＝１６
８／４２ｎ ＝１６
ｎ ＝８４
2007-09-01 13:14:58 補充：
１．ｔｈｅ ｍｏｒｅ ｅｘｐｅｎｓｉｖｅ ｏｆ ｔｈｅ ｃｅｒａｍｉｃ ｃａｔ ｉｓ １２＋３＝１５
2007-09-11 13:38:33 補充：
1.第2題答案是錯的.答案應該是2
2.沒有第3題的答案!!!!!
（１００－７）＝９３
４ｎ＋（３ｎ＋３）＝７ｎ＋９
９３＝７ｎ＋９
ｎ＝１２
２．３０ｗ＋２０（ｗ＋１）／ｗ＋ｗ＋１＝２４
５０ｗ＋２０ ＝４８ｗ＋２４
２ｗ ＝４
ｗ ＝２
３．ｌｅｔ ｔｈｅ ｏｒｉｇｉｎａｌ ｎｕｍｂｅｒ ｏｆ ｔｈｅ ｇｌａｓｓ ｂｅａｄｓ ｂｅ ｎ
ｎ－（１／２＋１／６＋１／７）ｎ＝１６
ｎ－（３４／４２）ｎ ＝１６
８／４２ｎ ＝１６
ｎ ＝８４
2007-09-01 13:14:58 補充：
１．ｔｈｅ ｍｏｒｅ ｅｘｐｅｎｓｉｖｅ ｏｆ ｔｈｅ ｃｅｒａｍｉｃ ｃａｔ ｉｓ １２＋３＝１５
2007-09-11 13:38:33 補充：
1.第2題答案是錯的.答案應該是2
2.沒有第3題的答案!!!!!
收錄日期: 2021-04-13 15:25:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070901000051KK02014