化簡呢條式：
5m-5-2(2m+1)
俾埋過程!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
加埋解釋!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
------------------------------------------------------------------------------------------
THX!
代數(小6 to 中一)
2007-09-01 7:44 pm
回答 (8)
2007-09-01 9:18 pm
5m-5-2(2m+1)
=5m-5-4m-2
=5m-4m-5-2
=m-7
=5m-5-4m-2
=5m-4m-5-2
=m-7
2007-09-01 8:42 pm
5m-5-2(2m+1)
=5m-5-4m-2
=5m-4m-7
=m-7
=5m-5-4m-2
=5m-4m-7
=m-7
2007-09-01 8:14 pm
化簡呢條式：
5m-5-2(2m+1)
我哋先解 2(2m+1)
2(2m+1)
= 2x2m + 2x1
= 4m+2
5m-5-2(2m+1)
= 5m-5-(4m+2) →括號前有負號
= 5m-5-4m-2 → 點解+2變咗-2? 因為要拆括號,受前面負號影響,負正得負。
= 5m-4m-5-2 →將有5m同-4m一齊放, -5同-2一齊放, 令自己方便睇。
= 1m-7→ 1m的1可以省略
= m-7
5m-5-2(2m+1)
我哋先解 2(2m+1)
2(2m+1)
= 2x2m + 2x1
= 4m+2
5m-5-2(2m+1)
= 5m-5-(4m+2) →括號前有負號
= 5m-5-4m-2 → 點解+2變咗-2? 因為要拆括號,受前面負號影響,負正得負。
= 5m-4m-5-2 →將有5m同-4m一齊放, -5同-2一齊放, 令自己方便睇。
= 1m-7→ 1m的1可以省略
= m-7
參考: me
2007-09-01 7:56 pm
5m-5-2(2m+1)
=5m-5-4m-2 (先拆括號, -2x2m, -2x1)
=(5-4)m-5-2 (係數還係數減,數字還數字減)
=m-7
=5m-5-4m-2 (先拆括號, -2x2m, -2x1)
=(5-4)m-5-2 (係數還係數減,數字還數字減)
=m-7
參考: me
2007-09-01 7:55 pm
5m-5-2(2m+1)
= 5m-5-4m-2
= 5m-4m-5-2
= m-7
代數的原理
首先將{ -2(2m+1) } -2 x 2m + -2 x +1
點解要用（－２）乘？計（括胡數）（代數）要計埋數字前面既 正負符號 即＋and －
然後將整條算式入面相同種類的數擺埋一齊， 即5m-4m-5-2
就計到嫁啦
= 5m-5-4m-2
= 5m-4m-5-2
= m-7
代數的原理
首先將{ -2(2m+1) } -2 x 2m + -2 x +1
點解要用（－２）乘？計（括胡數）（代數）要計埋數字前面既 正負符號 即＋and －
然後將整條算式入面相同種類的數擺埋一齊， 即5m-4m-5-2
就計到嫁啦
參考: me
2007-09-01 7:48 pm
5m-5-2(2m+1)
=5m-5-4m+2
=5m-4m-5+2
=m-7
答案係m-7
=5m-5-4m+2
=5m-4m-5+2
=m-7
答案係m-7
收錄日期: 2021-04-13 13:51:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070901000051KK01602