數學問題(急用)

1. 6

2. 4

3. -6

4. 1

1. abc = (-2) x 3 x (-1) = 6

2. -a-(-b)+c = -(-2)-(-3)+(-1) = 2+3-1 = 4

3. 2a-b-c = 2 x (-2) - 3 - (-1) = -4-3+1 = 0

4. a+b
------
c

-2 + 3
= ----------
-1


1
= ----
-1

= -1


5.（－１）－（－３）＋（＋９） = -1+3+9 = 11

6.（－３６）＋（－９）－（－１８）= -36-9+18 = 27

7.（－８）Ｘ（－２）Ｘ（＋３）= 16 x 3 = 48

8.（＋３）除（－７）除（＋　七分之一　）

3 3 3
------------------ = ------------- = --------
(-7) -7 x 7 -49
-----------
1
( ------)
7

1. 6
2. 4
3. -6
4. -1

當a= -2 ， b=3，c= -1

1.abc
= -2 x 3 x (-1)
= 6

2. -a-(-b)+c
=- ( - 2 ) - ( - 3 ) + ( -1 )
= 2 + 3 - 1
= 4

3.2a-b-c
=2 x ( - 2) - 3 -( -1 )
= - 4 - 3 + 1
= - 6

4.a+b
------
c
= - 2 x 3
------
- 1
= 6

其實你係咪想求C? 你已經過左C係-1
基本上A B C你都講晒我知...我想知你求咩未知數-V-"

2007-08-31 17:40:46 補充：
@我MSN詳細D教下你. [email protected]

1. abc
= (-2)(3)(-1)
= 6

2. -a-(-b)+c
= -(-2)-(-3)+(-1)
= 4+3-1
= 6

3. 2a-b-c
= 2(-2)-(3)-(-1)
= -4-3+1
= -6

4. a+b
= (-2)+(3)
= -2+3
= 1

不好意思~
我不明白你最後說的'c'~
所以可能第4題不準確...

希望可以幫到你啦~

2007-08-31 17:42:03 補充：
如果你第4題是想這樣說: a+b-c= (-2)+(3)-(-1)= -2+3+1= 1+1= 2

2007-08-31 17:43:26 補充：
對不起~第二題計錯了~應該是這樣的:2. -a-(-b)+c= -(-2)-(-3)+(-1)= 2+3-1= 4

當a= -2 ， b=3，c= -1

1.abc
= -2x3x-1
=6

2. -a-(-b)+c
=-(2)-(-3)+1
=-2+3+1
= 2


3.2a-b-c
=2x(-2)-3-1
= -4-3-1
=-8

4.a+b-c ????????
= -2+3+(-1)
= -2+3-1
=0

1.6
2.0
3.-6
4.-1

1.
abc
=(-2)(3)(-1)
=6

2.
-a-(-b)+c
=-(-2)-(-3)+(-1)
=2+3-1
=4

3.
2a-b-c
=2(-2)-(3)-(-1)
=-4-3+1
=-6

4.
a+b
=-2+3
=1