maths!!!!!!!

2007-08-31 8:34 pm
1.make r the subject of the formula p=2r+q

2.s=a/1-r.
2a. if a=8 and r=-3, find the value of s.
2b.change the subject of the formula to r.
2c.if s=6 and a=3, find the value of r.

回答 (3)

2007-08-31 8:40 pm
✔ 最佳答案
1.make r the subject of the formula p=2r+q
p=2r+q
p-q=2r
p-q/2=r
r=p-q/2


2.s=a/1-r.

2a. if a=8 and r=-3, find the value of s.
a=8, r=-3
s=8/1-(-3)
s=8/1+3
s=2

2b.change the subject of the formula to r.
s=a/1-r
s(1-r)=a
1-r=a/s
-r = a/s-1
r = 1-a/s

2c.if s=6 and a=3, find the value of r.
r = 1-a/s
r = 1 - 3/6
r = 1 - 1/2
r = 1/2
參考: myself~
2007-08-31 8:48 pm
1.make r the subject of the formula p=2r+q
Ans:
p=2r+q
p-q=2r
r=(p-q)/2
---------------------------------------
2.s=a/1-r.
2a. if a=8 and r=-3, find the value of s.
Ans:
s=a/1-r.=8/[1-(-3)]=8/4=2//
2b.change the subject of the formula to r.
Ans:
s=a/1-r
s(1-r)=a
s-sr=a
a-s=sr
r=(a-s)/s//
2c.if s=6 and a=3, find the value of r.
Ans:
r=(a-s)/s=(3-6)/6= -3/6= -1/2//
2007-08-31 8:44 pm
1. p=2r+q
p-q=2r
r=(p-q)/2

2a. puta=8 and r=3 into s=a/1-r
s=8/1-3
=8/ -2
= -4

2b. s=a/1-r
s(1-r)=a
s-rs=a
s-a=rs
r=(s-a)/s
r=1-a/s

2c. put s=6 and a=3 into r=1-a/s
r=1-3/6
=1-1/2
=1/2


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